User:Dmitrii Kouznetsov/Analytic Tetration

Fig.0. Graphic of analytic tetration Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f=F_2(x)=\exp_2^x(1)} versus Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x} .

In this page, I collect pieces and figures, which can be used to build-up tetration.

Abstract

Analytic tetration is defined as mathematical function that coincides witht the tetration at integer values of the argument and is analytic outside the negative part of the real axis. Existence of such a function is postulated; and arguments in favor of uniqueness of such a function are considered. The algorithm of evaluation is suggested. Examples of evaluation, pictures and tables are supplied. The application and the generalization is discussed.

Preface

The colleagues indicated so many misprints in my papers about tetration, posted at my homepage , that I want to give them opportunity to correct them in real time.

Especially I invite

• Arthur Knoebel
• Henryk Trappmann
• Andrew Robbins

to edit this file.

I consider the topic very important and urgent. The analytic tetration should be investigated and discussed right now; overvice, the non-analytic extension may become an ugly standard in mathematics of computation; the implementation of hige numbers with non-analytic tetration would make difficult realization of arithmetic operations and cause a lot of incompatibilities.

This is my apology for posting this research now, while the rigorous proof of existence and uniqueness of the analytic tetration is not yet found. My believe is based on the numerical check of the hypothesis of the existence and uniqueness, on smallness of the residual at the substitution of the function to the tetration equation and beauty of the resulting pictures. I cannot imagine that the agreement with 14 decimal digits occurs just by occasion without deep mathematical meaning.

In such a way I apologize for postulating of statements which should be prooven by the rigorous mathematical deduction.

Introduction

Quick start

Roughly, super-exponential

(1) Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle F_b(z)=\exp_b^z(1)}

is combination of Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle z} exponentials on base Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle b} . For example,

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~ F_b(0)=\exp_b^0(1)=1}

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~ F_b(1)=\exp_b(1)=b}

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~ F_b(2)=\exp_b^2(1)=\exp_b(\exp_b(1))=b^b}

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~ F_b(3)=\exp_b^3(1)=\exp_b\Big(\exp_b\big(\exp_b(1)\big)\Big)=b^{b^b}}

and so on. However, such definition is good only for positive integer values of Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle z} . In general, the superexponential can be defined through the Abel equation

(2) Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~\exp_b\Big(F_b(z)\Big)=F_b(z+1) }

with additional condition that

(3) Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~F_b(0)=1}

Then, at least for positive values of Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~b} and positive integer values of Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~z} , such a definition can be used for the evaluation of tetration.

In this paper, the way to define tetration for non-integer argument is described. For real values of the argument, at Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~b=2} , such a tetration is plotted on figure 0. In the following sections, I describe, why is it so important, how to define the tetration for non-integer values of the argument, how can it be evaluated with high precision and why it is the only correct way to define analytic tetration.

Table of superfunctions

There exist many basefuncitons such that the supercunctions can be expressed in the closed form. For some function Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle F} such that both Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle F} and Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle F^{-1}} can be expressed with simple and explicit formulas, the basefunciton

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle H(z)=F(1+H^{-1}(z))} .

In such a way, the table below can be constructed.

Additional argument

One can consider to add the additional argument, replacing Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~\exp_b(1)} to Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~\exp_b(a)} . This may have sense, while Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~z} is allowed to have only integer values. However, at the implementation of "good" tetration, the "argument" Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~a} can be considered as inverse superexponential of some argument, Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~a=F_b(\alpha)} ; then, Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~\exp_b^z(a)=F_b\Big(F_b(\alpha) \Big)} ; in the way, similar to that of convential logarithms: it is sufficient to investigate properties of natural logarithm ln; then, any other can be expressed as Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \log_b(z)=\ln(z)/\ln(b)} .

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle  \exp_b^n(\exp_b^m(z))=\exp_b^{m+n}(z) }

The exponentiation of tetration is equivalent to increment of its argument. While summaton operation forms the group, exponentiation does too.

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \exp_b^m(F_b(z))=F_b(z+m)}

The generalization to non-integer values of Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle m} is possible. While writing formal expressions (and assuming existence of the inverse function Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle F^{-1}} ), the specific preperties of exponential function are not used; and the generalization is possible. Such generalization is described in article User:Dmitrii Kouznetsov/loginal.

Inverse function and group properties

In this section, I write Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~F} instead of Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~F_b} and Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~\exp(z)} instead of Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~\exp_b(z)} ; omitting indices. However, you may recover them at any moment.

(I am not sure which notation is best. D.)

The speculation of the previous subseciton can be written shorter.

Assume there exist function Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~F^{-1}} such that Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~ F\Big(F^{-1}(z)\Big)=z} .

Let Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~s=\exp^u(t)=F\Big(u+F^{-1}(t)\big)} and Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~q=\exp^v(s)=F\Big(v+F^{-1}(s)\big)} .

Then Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~q =\exp^v\Big( \exp^u(t) \Big) =F\Big(v+F^{-1}\Big(F(u+F^{-1}(t))\Big)\Big) =F\Big(v+u+F^{-1}(t)\Big) } .

You can put subscript Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~_b} to Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~F} and Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~\exp} in the defuction above, and it will be seen, that we have no need to deal with funciton of 2 variables, considering Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \exp_b^z(x)} ; it can be expressed in terms of Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle F_b(z)} . However, we need to specify, what set shold be Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~t} and Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~s} from in the deduction above: must they be positive integer, or they can be real, of they can be also complex numbers.

History of tetration and huge numbers

Perhaps, every researcher used to see diagnostivs "floating overflow" at the evlauation of an expression with huge numbers....

Abel equation

Assume, the tetration Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle F} is defined with the Abel equation

(10) Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle  \exp_b(F(z))=F(z+1)}

and assume the condition

(11) Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle  F(0)=1}

Asymptotic

The analytic extension of tetration Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle ~F(z)} is supposed to grow fast along the real axis of the complex $z$-plane, at least for some values of base $b$. However, it has no need to grow infinitely in the direction of imaginary axis. For mathematics of computation, it would be better, if $F(x+{\rm {i}}y)$ remains bounded at $y\rightarrow +\infty$. Consider this possibility.

Assume, there exist solution $F(z)$ of equations (10), (11), analytic in the $\Re (z)\geq 0$, with, probably, countable number of cuts and singularities at $\Re (z)<0$, with exponential asymptotic behavior

(12) $F(z)=L+\varepsilon (z)+o{\big (}\varepsilon (z)^{2}{\big )}$

within some range, where

(13) $\varepsilon (z)=\exp(Qz+r)$,

$Q$ and $r$ are fixed complex numbers, and $L$ is eigenvalue of logarithm, solution of equation

(14) $x=\log _{b}(x)$.

© Image: Dmitrii Kouznetsov
FIg.1. Example of graphic solution of equation $x=\log _{b}(x)$ for $b={\sqrt {2}}$ (two real solutions, $x=2$ and Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x=4} ), Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle b=\exp(1/\rm e)} (one real solution Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x=\rm e} ) Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle b=2} (no real solutions).

Solutions of equation (14) are called fixed points of logarithm. Three examples of graphical solution of equation (14) are shown in figure 1 for Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle b=\sqrt{2}} , $b=\exp(1/{\rm {e)}}$, and $b=2$.

The black line shows function $y=x$ in the $x,y$ plane. The colored curves show function $y=\log _{b}(x)$ for cases $b={\sqrt {2}}$ (red), $b=\exp(1/{\rm {e)}}$ (green), and $b=2$ (blue).

At $b={\sqrt {2}}$, there exist 2 solutions, $x=2$ and $x=4$.

At $b=\exp(1/{\rm {e)}}$ there exist one solution $x={\rm {e}}$.

and $b=2$, there are no real solutions.

In general,

• at $b<\exp(1/{\rm {e)}}$ there are two real solutions
• at $b=\exp(1/{\rm {e)}}$, there is one soluition, and
• at $b>\exp(1/{\rm {e)}}$ there esist two solutions, but they are complex.

In particular, at $b={\sqrt {2}}$, the solutions are
$x=L_{{\sqrt {2}},1}=2$ and $x=L_{{\sqrt {2}},2}=4$
.

At $b=2$, the solutions are
$x=L_{2}\approx 0.824678546142074222314065+1.56743212384964786105857\!~{\rm {i}}$ and
$x=L_{2}^{*}\approx 0.824678546142074222314065-1.56743212384964786105857\!~{\rm {i}}$.

At $b={\rm {e}}$, the solutions are
$x=L_{\rm {e}}\approx 0.318131505204764135312654+1.33723570143068940890116\!~{\rm {i}}$ and
$x=L_{\rm {e}}^{*}\approx 0.318131505204764135312654-1.33723570143068940890116\!~{\rm {i}}$.

Few hundred straightforward iterations of equation (14) are sufficient to get the error smaller than the last decimal digit in the approximations above.

The solutions $x=L_{1}$ and $x=L_{2}$ of equation (14) are plotted in figure 2 versus $\beta =\ln(b)$ with thin black lines. Let $L_{1}<L_{2}$, and only at $\ln(b)=1/e$, the equality $L_{1}=L_{2}$ takes place.

FIg.2. parameters of asymptotic of tetration versus logarithm of the base

The thin black solid curve at $\beta \geq 1/{\rm {e}}$ represents the real part of the solutions $L$ and $L^{*}$ of (14); the thin black dashed curve represents the two options for the imaginary part; the two solutions are complex conjugaitons of each other. Let $\Re (L)>0$.

Increment and periodicity

Parameter $Q$ in equaiton (13) has sense of asymptotic increment. Consider possible values of $Q$.

Substitution of expression (13) into the eq. (12) gives
$L+\varepsilon (z){\rm {e}}^{Q}+o(\varepsilon (z))=\exp \!{\Big (}\ln(b)(L+\varepsilon (z)+o(\varepsilon (z)){\Big )}$ Using equation (14) gives

$L+\varepsilon (z){\rm {e}}^{Q}+o(\varepsilon (z))=L~{\Big (}1+\ln(b)\varepsilon (z)+o(\varepsilon (z)){\Big )}$

Then

(16) $Q=\ln(\ln(b))+\ln(L)$.

At $\ln(b)<1/{\rm {e}}$, the two real increments correspond the the two real eigenvalues of logarithm. Let Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle Q_1=\ln(\ln(b))+\ln(L_1) } and Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle Q_2=\ln(\ln(b))+\ln(L_2) } . Both Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle Q_1 } and Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle Q_2 } are plotted in Figure 2 with thick solid lines; Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle Q_1\le 0 } and Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle Q_2\ge 0 } , and only at Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \ln(b)=1/\rm e } the equality Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle Q_1= Q_2= 0 } holds.

In such a way, at Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \ln(b)<1/\rm e} , there exist positive increment, which corresponds to Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle L_2} and means, that the perturbation Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \epsilon(z)} of the stationary solution grows up in the diredtion of real axis; there exist negative increment (decrement, if you like), which corresponds to Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle L_1} and indicates, that the perturbation grows up in the opposite direction. At Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 0<\ln(b)<2/\rm e} , there may exist tetration Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle F(z)} with two different asumptotics. At large positive values of Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \Re(z)} it decays to the Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle L_1} and At large negative values of Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \Re(z)} it decays to the Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle L_2} .

At Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \ln(b)\ge 1/\rm e } , there exist two possible increments, Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle Q} and Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle Q^*} . The real part of Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle Q} is plotted with thick solid line, and the imaginary part is shown with thick dashed line. The real part is positive; id est, the perturbation Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \varepsilon(z)} grows up in the direction of real axis.

For computational mathematics, it would be good ot construct the solution, that decays both in the direction of the imaginary asis and in the opposite direction. Such a solution should have asymptotics (12),(13) at large positive values of the imaginary part of the argument and its conjugation at large negative imaginary part of the argument.

The exponential asymptotics implies the asumptotic perioditity. The period

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle T=\frac{2 \pi{\rm i}}{Q} }

is shown in FIgure 2 with dotted lines; for the case when period is negative, the minus period is plotted. It is amaising, that at Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \ln(b)>1/\rm e} , the imajinary part is slightly larger than unity and remains almost constant.

In particular, at Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle b=\sqrt{2}} , the periods are

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle T_{\rm b,1} = \frac{2\pi \rm i}{Q_{b,1}}\approx -17.143148179354847104 \!~\rm i }
Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle T_{\rm b,2} = \frac{2\pi \rm i}{Q_{b,2}}\approx ~ 19.236149042042854710 \!~\rm i }

At Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle b=2} , the asymptotic period
$T=5.58414243554338946020010+1.05421836033693734654000\!~{\rm {i}}$;
and at $b={\rm {e}}$, the asymptotic period
$T=4.44695072006700782711227+1.05793999115693918376341\!~{\rm {i}}$.

Uniqueness

While one deal with solutions of system (10), (11) at the real axis, one imagine some real-analytic extension shown in Figure 0 and consider also

(100) $G(z)=F(z+k(z))$

where

(101) $k(z)=\sum _{n=-\infty }^{\infty }\alpha _{n}\exp(2\pi {\rm {i}}nz)$

Such a funciton is also soluiton of the Abel equation; at

(102) $\alpha _{-n}=(\alpha _{n})^{*}$

and

(103) $\alpha _{0}=-\sum _{n\neq 0}\alpha _{n}$

function $~G$ is real and passes through the same points as </math>~F</math> at integer values of the argument.

and at small values of coefficients $\alpha$, function $~G$ looks smooth, and it is difficult to guess, which of them is "true". For this reason, for the standard mathematical representation, the non-analytic stepwice funciton uxp was suggested .

However, the difference between functions $~F$ and $~G$ becomes seen, if one of them, for example, $~F$, is analytic and regular in some wide range, function $~G(z)$ will be analytic only within the strip $~|z|<y_{0}$; order of magnitude of $~y_{0}$ can be estimated with

$y_{0}\approx {\rm {MIN}}_{n}~{\frac {\ln(2/|\alpha _{n}|)}{2\pi n}}$

At larger values of the imaginary part of the argument, the periodic function $k$ takes huge values, including various negative integers. Namely at these values, function $~F$ has singulatities.

Various functions may satisfy equations (2),(3). For an abstract excersise in comlex functional analysis, all animals are created equal. However, for the applicaitons in the computational mathematics, some of them are more equal than other . As such a more equal animal we should choose the solution with simplest behavior, with minimum of singulatities, and easiest for the evaluation.

At small base, both values of quasiperiod are pure imaginary. This periodic or quasi-periodic behavior is similar to that of the conventional exponential, but function $~F$ does not grow to infinity in the direction of the real axis, aproaching eigenvalue $L$ of logarithm. One example of such a behavior $~b={\sqrt {2}}$ is shown in Figure 3 for $~b={\sqrt {2}}$. The following section describes, how it was ploted.

At $~b>\exp(1/{\rm {e}})$ values of period $T$ are complex; and $\Re (T)>0$. This corresponds to the exponential growth of the asymptotic solution in the direction of the real axis; at large positive values of $\Re (Qz)$ the asymptotic does not approximate the function which grows faster than any exponential.

Examples of tetration at different bases

Small base. Base $b={\sqrt {2}}$

Fig.3a. Tetration $f=F(z)$ at the complex $z$-plane. Levels of integer $\Re (f)$ and levels of integer $\Im (f)$ are shown with thick lines.

For evaluation of Tetration we need to assume that it exists, and has asymptotic (30).

Consider the case of $1<b<\exp(1/{\rm {e)}}$. at fixed values of real part of the argument, the function has periodic behavior in the direction of imaginary axis, as it is shown in Fig. 3. In this figure, the example with $b={\sqrt {2}}$ is used. Function is periodic; period $T\approx 17.1431~{\rm {i}}$.

The limiting values:

$\lim _{x\rightarrow \infty }F_{\sqrt {2}}(x+{\rm {i}}y)=2$

$\lim _{x\rightarrow -\infty }F_{\sqrt {2}}(x+{\rm {i}}y)=4$

At non-zero values of the imaginary part of the argument, the function decays to these asymptotiv values.

At the real axis, the $~F(z)$ has cut at $z\leq -2$.

Due to the periodicity, the function has cuts also at

$Z+Tn\leq -2$ for integer $~n$.

As all other tetrations, it has singularity at $z=-2$, $~F(-1)=0$ and $~F(0)=1$.

Base $b={\sqrt {2}}$, alternative tetration $G$

Fig.3b. Tetration $f=G(z)$ at the complex plane $z=x+{\rm {i}}y$. Levels of integer $\Re (f)$ and levels of integer $\Im (f)$ are shown with thick lines.

Along the real axis, such a solution grows up faster than any exponential; it is always larger than 4 and therefore cannot be equal to unity; so, it is not possible to satisfy condition $G(0)=0$ just shifting its argument for some constant. The behavior of tetration $G_{\sqrt {2}}$ along the real axis makes it similar to that of tetrations with $b>\exp(1/{\rm {e)}}$; although, the larger $b$, the larger is the growth.

More alternative tetrations

Alternative tetration $G$ as solution of equation (1) can be calculated if we withdraw condition (2), and substitute it to $G(z)=L_{b,2}+\exp(Q_{2}z)+o(\exp(Q_{2}z))$ Such a solution is shown in Figure 3b.

Other, more singular tetrations can be obtained by light periodic deformation of the argument.

Base 2. Ackermann function

FIg.4. Ackermann function $f=A(4,z)=F_{2}(z+3)-3$ at the complex $z$ plane. Grid covers the range ( $-10\leq \Re (z)\leq 10~,~-4\leq \Im (z)\leq 4$ with unit step. Levels of integer values of the real part and the same for imaginary part are shown with thick lines.

Tertration at base 2 can be expressed through the 4th Ackermann function $F_{2}(z)=A(4,z-3)+3$ This Ackermann function is plotted in fig.4. As base $b>\exp(1/{\rm {e)}}$, the function is not periodic. However, there are asymptotic periods $L$ and $L^{*}$ in the upper and lower half-planes. In vicinity of positive part of the real axis, the function shows rapid growth, and it is not possible to draw the levels there. All the singularities of the Ackermann function are at the negative integer values smaller than $-4$.

Base e. Natural tetration

Fig.5.Analytic tetration at the base e , $f=F_{\rm {e}}(z)$ in the complex $z$plane. The grid covers the range ($-9\leq \Re (z)\leq 9$, $-4\leq \Im (z)\leq 4$). Levels $|f|=\exp(0),\exp(\pm 1),\exp(\pm 2),..$ and levels ${\rm {Arg}}(f)=0,\pm 1,\pm 2,\pm 3$ are shown with thick lines.

Base $b-{\rm {e}}$ is the most natural choise. In this case, the increment $Q$ is equal to the asymtotic value $L$.

At the translation for inity along the real axis,

Base e. Superlogarithm

Fig.7. Inverse of the analytic tetration $f=F_{\rm {e}}^{-1}(z)$ at the complex $z$-plane.

Inverse of the natural tetration can be considered as superlogarithm. Equilines of funciton $f=F_{\rm {e}}^{-1}(z)$ are shown in Figure 7. Levels of integer real part and those of integer imaginary part are shown with thick lines. This function has two branchpoints at eigenvalues of logarithm. In the figure, the cuts are placed along the lines $\Re (f)=-2$; then, the function is regular in vicinity of the real axis, approaching the limitig value $-2$ at $-\infty$ and slowly growing up at positive values of the argument.

Discussion

Analytic tetrations are shown for base $b={\sqrt {2}}$, $b=2$, and $b={\rm {e}}$. In the similar way, the tetration on other bases (for example, $b=10$ ) can be plotted.

Knowledge of the asymptotic behavior gives the key to the efficient evaluation.

references

See also the discussion at http://math.eretrandre.org/tetrationforum/forumdisplay.php?fid=3

Table of superfunctions

There exist many basefuncitons such that the supercunctions can be expressed in the closed form. For some function $F$ such that both $F$ and $F^{-1}$ can be expressed with simple and explicit formulas, the basefunciton

$H(z)=F(1+F^{-1}(z))$.

In such a way, the table below can be constructed.

$H(z)$	$F(z)$	$F^{-1}(z)$	comment
$z+\!\!+$	$b+z$	$z-b$
$z+b$	$bz+c$	$(z-c)/b$
$cz+c$	$(b^{z}+{\frac {c}{1-b}})d$	$\log _{b}{\frac {z-{\frac {cd}{1-b}}}{d}}$
$b^{z}$	$\mathrm {tet} _{b}(z)$	$\mathrm {arctet} _{b}(z)$	tetration
$z^{b}$	$\exp(b^{z})$	$\log _{b}(\ln(z))$
${\big (}a^{b}+z^{b}{\big )}^{1/b}$	$az^{1/b}$	$(z/a)^{b}$
$\ln(a+\mathrm {e} ^{z})$	$\ln(az)$	$\exp(z)/a$
$az/(z+a)$	$a/z$	$a/z$	amaising, $F=F^{-1}$
$2z^{2}-1$	$\cos(\pi 2^{z})$	$\log _{2}(\arccos(z)/\pi )$
$H(z)$	$F(z)$	$F^{-1}(z)$
$P(H(Q(z)))$	$P(F(z))$	$F^{-1}(Q(z))$	P(Q(z))=z